Yarıçap $r = 5 \text{ mm} = 0.5 \text{ cm}$
Özkütle $\rho = 1 \text{ g/cm}^3$
$\pi = 3$
Kürenin hacmi:
$V = \frac{4}{3} \pi r^3$ $V = \frac{4}{3} \cdot 3 \cdot (0.5)^3$ $(0.5)^3 = 0.125$ $V = 4 \cdot 0.125 = 0.5 \text{ cm}^3$
Kütle:
$m = \rho \cdot V = 1 \cdot 0.5 = 0.5 \text{ gram}$
Cevap: 0.5 gram